Ang Kahulugan Ng Kudas
Ang kahulugan ng kudas
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Kudos
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A 2.5 L Of Nitrogen Gas Exerts A Pressure Of 760 Mmhg At 473k.What Temperature Is Needed To Reduce The Volume To 1.75l At 1140 Torr?
a 2.5 L of nitrogen gas exerts a pressure of 760 mmhg at 473k.what temperature is needed to reduce the volume to 1.75L at 1140 torr? Hello! A 2.5 L of nitrogen gas exerts a pressure of 760 mmhg at 473k.what temperature is needed to reduce the volume to 1.75L at 1140 torr ? We have the following information: V1 (initial volume) = 2.5 L V2 (final volume) = 1.75 L T1 (initial temperature) = 473 K T2 (final temperature) = ? (in Kelvin) P1 (initial pressure) = 760 mmHg → P1 (initial pressure) = 1 atm P2 (final pressure) = 1140 torr (in atm) 1 atm --- 760 torr x atm ---- 1140 torr 760x = 1140 x = 1140/760 x = 1.5 atm → P2 (final pressure) = 1.5 atm ***Note: In SI the pressure can be mmHg or atm Now, we apply the data of the variables above to the General Equation of Gases, lets see: multiply the means by the extremes Answer: The temperature is 496.65 Kelvin ________________________________ I Hope this helps, greetings ... Dexteright02! =)
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